ThermodynamicsHard
Question
The molar entropy of a constant volume sample of neon at 500 K if it is 46.2 cal /K-mol at 250 K is (ln 2 = 0.7)
Options
A.2.1 cal/K-mol
B.44.1 cal/K-mol
C.48.3 cal/K-mol
D.46.2 cal/K-mol
Solution
$\Delta S = n.C_{V,m}.\ln\frac{T_{2}}{T_{1}}$
$S_{500\text{ K}} - 46.2 = 1 \times \frac{3R}{2} \times \ln\frac{500}{250} $$$\therefore S_{\text{500 K}} = 48.3\text{ Cal/K-mol}$$
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
A system absorbs 100 kJ heat in the process shown in the figure. What is ΔU for the system?...An amount of 2 mole of CO was in the small cubical container of length (l = a) at 57°C. The gas was taken out completely...What is the change in internal energy when a gas contracts from 325 ml to 125 ml at a constant pressure of 2 bar, while ...One mole of a non-ideal gas undergoes a change of state (2 atm, 3 L, 95 K) → (4 atm, 5 L, 245 K) with a change in intern...Heat of combustion of ethanol at constant pressure and at temperature TK (= 298 K) is found to be - q J mol-1. Hence, he...