ThermodynamicsHard

Question

Inversion temperature is defined as the temperature above which a gas gets warm up and below which, the gas become cooler, when expanded adiabatically. Boyle temperature for a gas is 20°C. What will happen to the gas if it is adiabatically expanded at 50°C?

Options

A.Heating
B.Cooling
C.Neither heating nor cooling.
D.First cooling then heating.

Solution

Boyle temperature, TB = 20 + 273 = 293 K

Inversion temperature, Ti = 2 × TB = 586 K = 313° C > 50° C

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