ThermodynamicsHard
Question
Work done by a sample of an ideal gas in a process A is double the work done in another process B. The temperature rises through the same amount in the two processes. If CA and CB are the molar heat capacities for the two processes, then
Options
A.CA = CB
B.CA > CB
C.CA < CB
D.Both, undefined
Solution
$\left| w_{A} \right| = 2 \times \left| w_{B} \right|\text{ But }\Delta U_{A} = \Delta U_{B}.\text{ Hence }q_{A} > q_{B}\text{ or, }\left( C_{A}.\Delta T \right) > \left( C_{B}.\Delta T \right) \Rightarrow C_{A} > C_{B}$
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
For a process to occur under adiabatic conditions, the essential condition(s) is/are...One mole of a non-ideal gas undergoes a change of state (2 atm, 3 L, 95 K) → (4 atm, 5 L, 245 K) with a change in intern...The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at 0oC...Which one of the following characteristics is not correct for physical adsorption of a gas on solid?...Which of the following statement(s) is/are true for ideal gas?...