ThermodynamicsHard

Question

Standard enthalpy of vaporisation ᐃvapHo for water at 100oC is 40.66 kJ mol-1. The internal energy of vaporisation of water at 100oC (in kJ mol-1) is
(Assume water vapour to behave like an ideal gas).

Options

A.+ 37.56
B.- 43.76
C.+ 43.76
D.- 40.66

Solution



For the above reqaction,
ᐃ ng = np - nr = 1 - 0 = 1
∴ 40.66 kJ mol-1 = + 1 × 8.314 × 10-3 × 373
= 40.66 kJ mol-1 - 3.1 kJ mol-1
= + 37.56 kJ mol-1

Create a free account to view solution

View Solution Free
Topic: Thermodynamics·Practice all Thermodynamics questions

More Thermodynamics Questions

A container of volume 1 m3 is divided into two equal parts by a partition. One part has an ideal diatomic gas at 300 K a...For complete combustion of ethanol, C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l), the amount of heat produced as measure...2 moles of an ideal monoatomic gas undergoes reversible expansion from (4 L, 400 K) to 8 L such that TV2 = constant. The...A thermally insulated vessel containing a gas whose molar mass is equal to 40 and ratio of specific heats is 1.5, moves ...An average human produces about 10 MJ of heat each day through metabolic activity. If a human body were an isolated syst...