ThermodynamicsHard
Question
What is the heat capacity of the ideal monoatomic gas undergoing the process shown in the figure?
Options
A.1.5R
B.2.5R
C.3.5R
D.1.33R
Solution
$PV^{x} = K \Rightarrow \frac{dP}{dV} = - x.\frac{P}{V} \Rightarrow - 1 = - x \times \frac{4}{2} \Rightarrow x = \frac{1}{2}$
$\therefore C_{m} = C_{V,m} + \frac{R}{1 - x} = \frac{3R}{2} + \frac{R}{1 - \frac{1}{2}} = 3.5R$
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