ThermodynamicsHard

Question

An ideal gas is expanded irreversibly from 5 L to 10 L against a constant external pressure of 1 bar. The value of heat involved (q) in this isenthalpic process is

Options

A.0
B.+500 J
C.+5 J
D.−500 J

Solution

$\Delta H = 0 \Rightarrow \Delta U = 0 \Rightarrow q = - w\text{ and }w = - P_{ert}\left( V_{2} - V_{1} \right) = - 1\text{ bar }(10L - 5L) = - 5\text{ L bar = } - \text{500 J}$

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