ThermodynamicsHard

Question

The average degree of freedom per molecule for a gas is 6. The gas performs 25 J of work when it expands at constant pressure. What is the amount of heat absorbed by the gas?

Options

A.25 J
B.50 J
C.75 J
D.100 J

Solution

$w = - 25\text{ J =} - nR.\Delta T$

$\Delta U = n.C_{V,m}.\Delta T = n.\left( \frac{6}{2}R \right).\Delta T = 75\text{ J} $$$\therefore q = \Delta U - w = 100\text{ J}$$

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