ThermodynamicsHard
Question
If all degree of freedom of a three- dimensional N-atomic gaseous molecules is excited, then CP/CV ratio of gas should be
Options
A.1.33
B.$1 + \frac{1}{3N - 3}$
C.$1 + \frac{1}{N}$
D.$1 + \frac{1}{3N - 2}$
Solution
$C_{V,m} = 3 \times \frac{1}{2}R + 3 \times \frac{1}{2}R + (3N - 6) \times R = (3N - 3)R$
$\therefore\gamma = \frac{C_{P}}{C_{V}} = 1 + \frac{R}{C_{V,m}} = 1 + \frac{1}{3N - 3}$
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