ThermodynamicsMedium
Question
A gas is heated at constant pressure. The fraction of heat absorbed used in doing work is
Options
A.$\frac{1}{\gamma}$
B.$1 - \frac{1}{\gamma}$
C.$\gamma - 1$
D.$\gamma$
Solution
$\frac{- w}{q_{p}} = \frac{nR.\Delta T}{n.C_{p,m}.\Delta T} = \frac{R}{\left( \frac{\gamma.R}{\gamma - 1} \right)} = 1 - \frac{1}{\gamma}$
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