ThermodynamicsHard
Question
When one mole of an ideal gas is compressed to half of its initial volume and simultaneously heated to twice its temperature, the change in entropy is
Options
A.Cv,m ln2
B.Cp,m ln2
C.R ln2
D.(Cv,m − R) ln2
Solution
$\Delta S = n.C_{v,m}.\ln\frac{T_{2}}{T_{1}} + nR.\ln\frac{V_{2}}{V_{1}} = 1 \times C_{v,m} \times \ln 2 + 1 \times R \times \ln\frac{1}{2} = \left( C_{v,m} - R \right).\ln 2$
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