ThermodynamicsHard
Question
When one mole of an ideal gas is compressed to half of its initial volume and simultaneously heated to twice its temperature, the change in entropy is
Options
A.Cv,m ln2
B.Cp,m ln2
C.R ln2
D.(Cv,m − R) ln2
Solution
$\Delta S = n.C_{v,m}.\ln\frac{T_{2}}{T_{1}} + nR.\ln\frac{V_{2}}{V_{1}} = 1 \times C_{v,m} \times \ln 2 + 1 \times R \times \ln\frac{1}{2} = \left( C_{v,m} - R \right).\ln 2$
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
Identify the correct statement regarding a spontaneous process...When an ideal diatomic gas is a heated at a constant pressure, the fraction of heat energy supplied which increases the ...A quantity of 1 g of water on evaporation at atmospheric pressure forms 1671 cm3 of steam. Heat of vaporization is 540 c...When a solid melts reversibly...What is the entropy change when 3.6 g of liquid water is completely converted into vapours at 373 K? The molar heat of v...