ThermodynamicsMedium

Question

The work done in the isothermal reversible expansion of argon gas at 27°C from 4 L to 16 L was equal to 4200 cal. What is the amount of argon subjected to such an expansion? (Ar = 40, ln4 = 1.4)

Options

A.5.0 g
B.20.0 g
C.200.0 g
D.48.1 g

Solution

$w = - nRT\ln\frac{V_{1}}{V_{2}} = - 4200 = - \frac{w}{40} \times 2 \times 300 \times \ln\frac{16}{4}$

$\therefore w = 200\text{ g}$

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