ThermodynamicsHard

Question

Two moles of helium gas undergoes a cyclic process as shown in the figure. Assuming ideal behaviour of gas, the magnitude of net work done by the gas in this cyclic process is

Options

A.0
B.100R ln2
C.100R ln4
D.200R ln4

Solution

$w_{AB} = - nRT.\ln\frac{P_{1}}{P_{2}} = - 2 \times R \times 300 \times \ln\frac{1}{2} = + 600R.\ln 2$

$w_{BC} = - nRT.\left( T_{2} - T_{1} \right) = - 2 \times R \times (400 - 300) = - 200R $$${w_{CD} = - nRT\ln\frac{P_{1}}{P_{2}} = - 2 \times R \times 400 \times \ln\frac{2}{1} = - 800R.\ln 2 }{w_{DA} = - nR\left( T_{2} - T_{1} \right) = - 2 \times R \times (300 - 400) = + 200R }{\therefore w_{net} = w_{AB} + w_{BC} + w_{CD} + w_{DA} = - 200R.\ln 2 = - 100R.\ln 4}$$

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