ThermodynamicsHard

Question

The expansion process of 2.0 moles of argon proceeds so that the gas pressure increases in direct proportion to its volume. The entropy change of the gas in this process if its volume increases 2.0 times, is (ln 2 = 0.7)

Options

A.+11.2 cal/K
B.−11.2 cal/K
C.+5.6 cal/K
D.−5.6 cal/K

Solution

$\Delta S = n.C_{V,m}.\ln\frac{P_{2}}{P_{1}} + n.C_{P,m}\ln\frac{V_{2}}{V_{1}}$

$= 2 \times \frac{3R}{2} \times \ln 2 + 2 \times \frac{5R}{2} \times \ln 2 = + 11.2\text{ cal/K}$

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