Two moles of an ideal gas [Cv,m (/JK−1 mol−1) = 20 + 0.01T(/K)] is heated at constant pressure from

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Two moles of an ideal gas [Cv,m (/JK−1 mol−1) = 20 + 0.01T(/K)] is heated at constant pressure from 27°C to 127°C. The amount of heat absorbed by the gas is

Accepted Answer

$q_{p} = n.\int_{T_{1}}^{T_{2}}{C_{p,m}.dT} = 2 \times \int_{T_{1} = 300\text{ K}}^{T_{2} = 400\text{ K}}\left( 28.314 + 0.01\text{ T} \right).dT$

$= 2\left\lbrack 28.314\left( T_{2} - T_{1} \right) + \frac{0.01}{2}\left( T_{2}^{2} - T_{1}^{2} \right) \right\rbrack = 6362.8\text{ J}$

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