ThermodynamicsMedium
Question
One mole of monoatomic ideal gas at T K is expanded from 1 L to 2 L adiabatically under a constant external pressure of 1 atm. The final temperature of the gas in Kelvin is
Options
A.T
B.$\frac{T}{2^{\left( \frac{5}{3} - 1 \right)}}$
C.$T - \frac{2}{3 \times 0.0821}$
D.$T + \frac{3}{2 \times 0.0821}$
Solution
$q = 0 \Rightarrow \Delta U = w \Rightarrow n.C_{v,m}.\left( T_{2} - T_{1} \right) = - P_{ert}.\left( V_{2} - V_{1} \right)$
Or $1 \times \frac{3}{2}R \times \left( T_{2} - T_{1} \right) = - 1\text{ atm } \times \left( 2\text{ L } - \text{1 L} \right)$
$\therefore T_{2} = T - \frac{2}{3 \times 0.0821}$
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