ThermodynamicsHard

Question

A system undergoes a process in which the entropy change is +5.51 JK–1. During the process, 1.50 kJ of heat is added to the system at 300 K. The correct information regarding the process is

Options

A.the process thermodynamically reversible.
B.the process is thermodynamically irreversible.
C.the process may or may not be thermodynamically reversible.
D.the process must be isobaric.

Solution

$\Delta S_{\text{Surr}} = - \frac{1.5 \times 10^{3}}{300} = - 5\text{ J/K}$

$\text{Now, }\Delta S_{\text{unit}} = \Delta S_{sys} + \Delta S_{\text{surr}} = 5.51 + ( - 5) = + 0.51\text{ J/K}$

Hence, the process is irreversible.

Create a free account to view solution

View Solution Free
Topic: Thermodynamics·Practice all Thermodynamics questions

More Thermodynamics Questions

A heat engine is operating in between 500 K and 400 K. If the engine absorbs 100 J heat per cycle, then which of the fol...A schematic plot of In Keq versus inverse of temperature for a reaction is shown below The reaction must be...Internal energy does not include:...Maximum work can a gas do, if it is allowed to expand isothermally against...A piston can freely move inside a horizontal cylinder closed from both ends. Initially, the piston separates the inside ...