ElectrochemistryHard
Question
Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m−1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte (in S m2 mol−1) is
Options
A.5 × 10−3
B.5 × 103
C.5 × 102
D.5 × 10−4
Solution
$K = G.G^{o} \Rightarrow \frac{\kappa}{1.4} = \frac{1/280}{1/50}$
$\Rightarrow \kappa = 0.25\text{ s }\text{m}^{- 1}\text{ for 0.5 M} $$$\text{Now, }\Lambda_{m} = \frac{\kappa}{C} = \frac{0.25}{0.5 \times 10^{3}} = 5 \times 10^{- 4}\text{ s }\text{m}^{2}\text{mo}\text{l}^{- 1}$$
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Emf for the cell reaction Zn|Zn2+(0.001M)||Zn2+(0.1M)|Zn...The conductivity of a saturated solution of AgCl at 298 K was found to be 3.40 × 10−6 Ω−1 cm−1; the conductivity of wate...From the following E° values for the half-cells:(i) D → D2+ + 2e−; E° = −1.5 V (ii) B+ + e− → B; E° = − 0.5 V(iii) A3− →...MnO4- + 8H+ + 5e- → Mn2+ + 4H2O ; Eo = 1.51 V ; ᐃGo1 = - 5 × 1.51 × FMnO2 + 4H+ + 2e- → Mn2+...How much the potential of a hydrogen electrode will change when its solution initially at pH = 0 is neutralised to pH = ...