ElectrochemistryHard
Question
Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m−1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte (in S m2 mol−1) is
Options
A.5 × 10−3
B.5 × 103
C.5 × 102
D.5 × 10−4
Solution
$K = G.G^{o} \Rightarrow \frac{\kappa}{1.4} = \frac{1/280}{1/50}$
$\Rightarrow \kappa = 0.25\text{ s }\text{m}^{- 1}\text{ for 0.5 M} $$$\text{Now, }\Lambda_{m} = \frac{\kappa}{C} = \frac{0.25}{0.5 \times 10^{3}} = 5 \times 10^{- 4}\text{ s }\text{m}^{2}\text{mo}\text{l}^{- 1}$$
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