ElectrochemistryHard
Question
Given : Eº(Cu2+ | Cu) = 0.337 V and Eo(Sn2+ | Sn) = - 0.136 V. Which of the following statements is correct?
Options
A.Cu2+ ions can be reduced by H2(g)
B.Cu can be oxidized by H+
C.Sn2+ ions can be reduced by H2(g)
D.Cu can reduce Sn2+
Solution
As EoCu2+ → Cu = 0.337 V > EoH+/H2
∴ Cu2+ can be reduced by H2.
∴ Cu2+ can be reduced by H2.
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