ElectrochemistryHard

Question

At 25°C, the molar conductance at infinite dilution for HCl solution is 4.25 Ω−1 m2 mol−1, while its specific conductance is 382.5 Ω−1 m−1. If the degree of dissociation is 90%, the molarity of solution is

Options

A.0.9 M
B.1.0 M
C.0.1 M
D.1.1 M

Solution

$\Lambda_{m} = \alpha.\Lambda_{m}^{o} = \frac{\kappa}{C}$

Or, $0.9 \times 4.25 \times 10^{- 2} = \frac{382.5}{C \times 10^{3}} \Rightarrow C = 0.1\text{ M}$

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