ElectrochemistryHard
Question
The EMF of a galvanic cell composed of two hydrogen electrodes is 272 mV. What is the pH of the solution in which the anode is immersed if the cathode is in contact with a solution of pH = 3?
Options
A.3
B.6.7
C.7.6
D.1.6
Solution
Cell reaction: H+(cathode, PH = 3) ? H+ (anode, PH =?)
$E_{cell} = 0 - \frac{0.059}{1}.\log\frac{\left\lbrack H^{+} \right\rbrack_{\text{anode}}}{\left\lbrack H^{+} \right\rbrack_{\text{Cathode}}} = 0.059\left\lbrack P_{\text{anode}}^{H} - P_{\text{Cathode}}^{H} \right\rbrack $$$\text{Or, 0.272 = 0.059}\left\lbrack P_{\text{anode}}^{H} - 3 \right\rbrack \Rightarrow P_{\text{anode}}^{H} = 7.6$$
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Copper can be deposited from acidified copper sulphate and alkaline cuprous cyanide. If the same current is passed for a...When silver chloride is dissolved in a large excess of ammonia, practically all silver ion can be assumed to exist in fo...To a beaker containing 0.1 M – HCl, a little pure solid AgCl is added. Both a silver and a hydrogen electrode (PH2 = 1.0...A gas Cl2 at 1 atm is bubbled through a solution containing a mixture of 1 M Br-1 and 1 M F-1 at 25oC. If the reduction ...For a closed-circuit Daniell cell, which of the following plots is the accurate one at a given temperature?...