ElectrochemistryHard
Question
The EMF of a galvanic cell composed of two hydrogen electrodes is 272 mV. What is the pH of the solution in which the anode is immersed if the cathode is in contact with a solution of pH = 3?
Options
A.3
B.6.7
C.7.6
D.1.6
Solution
Cell reaction: H+(cathode, PH = 3) ? H+ (anode, PH =?)
$E_{cell} = 0 - \frac{0.059}{1}.\log\frac{\left\lbrack H^{+} \right\rbrack_{\text{anode}}}{\left\lbrack H^{+} \right\rbrack_{\text{Cathode}}} = 0.059\left\lbrack P_{\text{anode}}^{H} - P_{\text{Cathode}}^{H} \right\rbrack $$$\text{Or, 0.272 = 0.059}\left\lbrack P_{\text{anode}}^{H} - 3 \right\rbrack \Rightarrow P_{\text{anode}}^{H} = 7.6$$
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