NEET | 2016ElectrochemistryEasy

Question

The pressure of H2 required to make the potential of H2 - electrode zero in pure water at 298 k is:

Options

A.

10-14 atm

B.

10-12 atm

C.

10-10 atm

D.

10-4 atm

Solution

Pt, H2(g)H+ Hydrogen electrode EH2/H+o = 0.0 Volt
H2(g) → 2H+(aq) + 2e-
[H+] = 10-7 M at 25oC (for Pure water)
E = -0.0591 2log [H+]2PH2
E = 0 = log [H+]PH2=0
∴ [H+]2=PH2
∴ PH2=10-14 atm

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