Calculate $\Lambda_{m}^{\infty}$ (in Ω−1 cm2 mol−1) for SrCl2 at 25°C, from the following data:Conc.

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Calculate $\Lambda_{m}^{\infty}$ (in Ω−1 cm2 mol−1) for SrCl2 at 25°C, from the following data:Conc. 0.25 M 1.0 MΛm (in Ω−1 cm2 mol−1) 260 250

Accepted Answer

$\Lambda_{m} = \Lambda_{m}^{o} - A\sqrt{C}\left( \text{for strong electrolyte} \right)$

$\text{Or, 260 = }\Lambda_{m}^{o} - A \times \sqrt{0.25}(1) $$${250 = \Lambda_{m}^{o} - A \times \sqrt{1.00}(2) }{\therefore\Lambda_{m}^{o} = 270\text{ oh}\text{m}^{- 1}\text{ c}\text{m}^{2}\text{ mo}\text{l}^{- 1}}$$

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