ElectrochemistryHard
Question
What would be the magnitude of the EMF of the following cell:
Pt(H2) =
Pt(H2)
at 25oC ? The ionization constant of acetic acid, Ka ~ 10-5, while that of formic acid, Ka ~ 10-4.
Pt(H2) =
Pt(H2) at 25oC ? The ionization constant of acetic acid, Ka ~ 10-5, while that of formic acid, Ka ~ 10-4.
Options
A. 0.0295 V
B.0.059 V
C.-0.059 V
D.-0.0295 V
Solution
At anode:
0.1 M acetic acid + 0.1 M sodium acetate ⇒ Acidic buffer.
∴ pHa = pKa + log
(pKa(CH3COOH) = 5)
pHc = 4
Ecell = -0.059(pHc - pHa) = -0.059(4 - 5) = 0.059 V
0.1 M acetic acid + 0.1 M sodium acetate ⇒ Acidic buffer.
∴ pHa = pKa + log
pHc = 4
Ecell = -0.059(pHc - pHa) = -0.059(4 - 5) = 0.059 V
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