ElectrochemistryHard
Question
The calomel electrode is reversible with respect to
Options
A.Hg22+
B.H+
C.Hg2+
D.Cl−
Solution
$Hg_{2}Cl_{2}(s) \rightleftharpoons Hg_{2}^{2 +}(aq) + 2Cl^{-}(aq)$
$Hg_{2}^{2 +}(aq) + 2e^{-} \rightleftharpoons 2Hg(I)$
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Given : Eº(Cu2+ | Cu) = 0.337 V and Eo(Sn2+ | Sn) = - 0.136 V. Which of the following statements is correct?...For the given cell, pt, Cl2/HCl||HCl/Cl2, pt (l atm) C1 C2(1 atm) The emf will be positive when :-...The EMF for the cell: Ag(s)|AgCl(s)|KCl(0.2 M)||KBr (0.001 M)|AgBr(s)|Ag(s) at 25°C is (Ksp(AgCl) = 2.0 × 10−10; Ksp(AgB...Fe is reacted with 1.0 M HCl. Eo for Fe / Fe2+ = + 0.34 V. The correct observation(s) regarding this reaction is/are :...The elctrode potentials for Cu2+ (aq) + e- → Cu+(aq) and Cu+ (aq) + e- → Cu (s) are +0.15 V and +0.50 V resp...