ElectrochemistryHard

Question

The equivalent conductivity of KCl at infinite dilution is 130 S cm2 eq-1. The transport number of Cl-1 ion in KCl at the same temperature is 0.505. The limiting ionic mobility of K+ ion, is

Options

A.6.67 × 10-4 cm2 sec-1 volt-1
B.5.01 × 10-3 cm2 sec-1 volt-1
C.3.22 × 10-4 cm2 sec-1 volt-1
D.2.00 × 10-4 cm2 sec-1 volt-1

Solution

= 0.505     or    λoCI- =  0.505 × 130 = 65.65  Scm2 eq-1.
λok+ =  F × UK+         or     UK+ = cm2 volt-1 sec-1.
= 6.67 × 10-4 cm2 volt-1 sec-1.

Create a free account to view solution

View Solution Free
Topic: Electrochemistry·Practice all Electrochemistry questions

More Electrochemistry Questions

When 0.1 mol MnO42- is oxidised the quantity of electricity required to completely oxidise MnO42- to MnO4- is...Zn | Zn2+ (C1)|| Zn2+ (C2)|Zn. for this cell ᐃG is negative if -...Indicator electrode is...The limiting molar conductivities ∧o for NaCl, KBr and KCl are 126, 152 and 150 S cm2 mol-1 respectively. The &#87...If the cell reaction is spontaneous then...