ElectrochemistryHard

Question

The equivalent conductivity of KCl at infinite dilution is 130 S cm2 eq-1. The transport number of Cl-1 ion in KCl at the same temperature is 0.505. The limiting ionic mobility of K+ ion, is

Options

A.6.67 × 10-4 cm2 sec-1 volt-1
B.5.01 × 10-3 cm2 sec-1 volt-1
C.3.22 × 10-4 cm2 sec-1 volt-1
D.2.00 × 10-4 cm2 sec-1 volt-1

Solution

= 0.505     or    λoCI- =  0.505 × 130 = 65.65  Scm2 eq-1.
λok+ =  F × UK+         or     UK+ = cm2 volt-1 sec-1.
= 6.67 × 10-4 cm2 volt-1 sec-1.

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