ThermochemistryHard

Question

What is the enthalpy change for the isomerization reaction?

CH2=CH–CH2–CH=CH–CH=CH2 (A) $\overset{\quad NaNH_{2}\Delta\quad}{\rightarrow}$ CH2=CH–CH=CH–CH=CH–CH3 (B)

Options

A.−584 kJ
B.−564 kJ
C.−544 kJ
D.−20 kJ

Solution

$\Delta H = 50 - 70 = - 20\text{ kJ}$

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