Calculate Δf Ho for aqueous chloride ion from the following data.½ H2(g) + ½ Cl2(g) → HCl(g): ΔfHo =

Question

Calculate Δf Ho for aqueous chloride ion from the following data.

½ H₂(g) + ½ Cl₂(g) → HCl(g): Δ_fH^o = −92.4 kJ

HCl(g) + nH₂O(l) → H⁺ (aq) + Cl⁻ (aq): ΔH^o = −74.8 kJ

Δ_fH^o (H⁺, aq.) = 0.0 kJ

Accepted Answer

$(a)\frac{1}{2}H_{2}(g) + \frac{1}{2}Cl_{2}(g) \rightarrow HCl(g);\Delta H^{o} = - 92.4\text{ KJ}$

$(b)HCl(g) + nH_{2}O(l) \rightarrow H^{+}(aq) + Cl^{-}(aq);\Delta H^{o} = - 74.8\text{ kJ} $$${(c)\frac{1}{2}H_{2}(g) + nH_{2}O(l) \rightarrow H^{+}(aq);\Delta H^{o} = 0 }{\text{Required T.C.E. is} }{\frac{1}{2}Cl_{2}(g) + nH_{2}O(l) \rightarrow Cl^{-}(aq);\Delta H^{o} = ? }{\text{From }(a) + (b) - (c);\Delta H^{o} = - 167.2\text{ KJ}}$$

Question

Options

Solution

More Thermochemistry Questions