ThermochemistryHard
Question
The enthalpy change (ᐃH) the reaction, N2(g) + 3H3(g) → 2NH3(g) is - 92.38 kJ at 398 K. The internal energy changed ᐃU at 298K is
Options
A.- 92.38 kJ
B.- 87.42kJ
C.- 97.34 kJ
D.- -89.9kJ
Solution
ᐃE = ᐃH - ᐃnRT
= - 92.38 -
= - 92.38 = 4.95 = - 87.47kJ
= - 92.38 -
= - 92.38 = 4.95 = - 87.47kJ
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