SolutionHard
Question
A liquid freezes at 7°C and boils at 77°C. If the Kf and Kb values for the liquid are 5.6 and 2.5 deg/molal, respectively, then the ratio of molar latent heat of fusion to molar latent heat of vaporization is
Options
A.1: 1
B.1: 3
C.2: 7
D.7: 3
Solution
$\frac{K_{f}}{K_{b}} = \frac{T_{f}^{o^{2}}/\Delta H_{\text{fus}}}{T_{b}^{o^{2}}/\Delta H_{\text{vap}}} \Rightarrow \frac{\Delta H_{\text{fus}}}{\Delta H_{\text{vap}}} = \left( \frac{T_{f}^{o}}{T_{b}^{o}} \right)^{2} \times \frac{K_{b}}{K_{f}} = \left( \frac{280}{350} \right)^{2} \times \frac{2.5}{5.6} = \frac{2}{7}$
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