The boiling point and freezing point of a solvent ‘A’ are 90.0°C and 3.5°C, respectively. The Kf and

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The boiling point and freezing point of a solvent ‘A’ are 90.0°C and 3.5°C, respectively. The Kf and Kb values of the solvent are 17.5 and 5.0 K-kg/mol, respectively. What is the boiling point of a solution of ‘B’ (non-volatile, non-electrolyte solute) in ‘A’, if the solution freezes at 2.8°C?

Accepted Answer

$\frac{\Delta T_{f}}{\Delta T_{b}} = \frac{K_{f}}{K_{b}} \Rightarrow \frac{\Delta T_{b}}{17.5} = \frac{5}{17.5} \Rightarrow \Delta T_{b} = 0.2^{o}C$∴ B.P. of solution = 90.2°C

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