SolutionHard
Question
If 100 mL of 1 M H2SO4 solution is mixed with 100 mL of 98% (W/W) of H2SO4 solution (d = 0.1 g mL), then
Options
A.Concentration of solution becomes half.
B.Volume of solution becomes 200 mL.
C.Mass of H2SO4 in the solution is 98 g.
D.Mass of H2SO4 in the solution is 19.6 g.
Solution
100 mL of 1 M H2SO4 + 100 mL (98%, d = 0.1) H2SO4
⇒ 100 × 1 M + 100 mL ×
⇒ 100 × 1 M + 100 × 1 M
∴ [H2SO4] =
= 1 M = 98 g/1000 mL
Mass of H2SO4 =
= 19.6 g
Concentration of each component becomes half of the initial
⇒ 100 × 1 M + 100 mL ×
⇒ 100 × 1 M + 100 × 1 M
∴ [H2SO4] =
= 1 M = 98 g/1000 mLMass of H2SO4 =
= 19.6 gConcentration of each component becomes half of the initial
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