SolutionHard
Question
The boiling point of a 2% (w/w) aqueous solution of a non-volatile and non-electrolyte solute is 0.102°C higher than that of pure water. If Kb for water is 0.52 K-kg/mol, the molecular mass of the solute is
Options
A.180
B.102
C.40
D.104
Solution
$\Delta T_{b} = K_{b}.m \Rightarrow 0.104 = 0.52 \times \frac{2/M}{98/1000} \Rightarrow M = 104$
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