JEE Main | 2026SolutionHard
Question
80 mL of a hydrocarbon on mixing with 264 mL of oxygen in a closed U-tube undergoes complete combustion. The residual gases after cooling to 273 K occupy 224 mL. When the system is treated with KOH solution, the volume decreases to 64 mL. The formula of the hydrocarbon is :
Options
A.[image/equation - edit required]
B.[image/equation - edit required]
C.[image/equation - edit required]
D.[image/equation - edit required]
Solution
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