SolutionHard
Question
A solution containing 30 g of a non-volatile solute exactly in 90 g water has a vapour pressure of 2.8 kPa at 298 K. On adding 18 g of water in the solution, the new vapour pressure becomes 2.9 kPa at 298 K. The molecular mass of the solute is
Options
A.23
B.69
C.34
D.43
Solution
$P = X_{2}.P^{o}$
$2.8 = \frac{90/18}{\frac{30}{M} + \frac{90}{18}} \times P^{o}\text{ and }2.9 = \frac{108/18}{\frac{30}{M} + \frac{108}{18}}.P^{o} $$$\therefore M = 23$$
Create a free account to view solution
View Solution FreeMore Solution Questions
The phase diagrams for the pure solvent (solid lines) and the solution (non-volatile solute, dashed line) are recorded b...Which aqueous solution can not be stirred with silver spoon:-...Select correct statements :...Two liquids A and B form an ideal solution at temperature T K. At T K, the vapour pressures of pure A and B are 55 and $...Relative decrease in vapour pressure of an aqueous solution containing 2 moles [Cu(NH3)3Cl] Cl in 3 moles H2O is 0.50. O...