SolutionHard
Question
The vapour pressure of pure benzene at a certain temperature is 0.85 bar. A non-volatile, nonelectrolyte solid weighing 0.5 g is added to 39.0 g of benzene. The vapour pressure of the solution then is 0.845 bar. Molar mass of the solid substance is
Options
A.169 g/mol
B.170 g/mol
C.85 g/mol
D.39 g/mol
Solution
$\frac{P^{o} - P}{P} = \frac{n_{1}}{n_{2}} \Rightarrow \frac{0.85 - 0.845}{0.845} = \frac{0.5/M}{39/78} \Rightarrow M = 169$
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