Water and chlorobenzene are immiscible liquids. Their mixture boils at 90°C under a reduced pressure

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Water and chlorobenzene are immiscible liquids. Their mixture boils at 90°C under a reduced pressure of 9.031 × 104 Pa. The vapour pressure of pure water at 90°C is 7.031 × 104 Pa and the molecular mass of chlorobenzene is 112.5. On mass percent basis, chlorobenzene in the distillate is equal to

Accepted Answer

$\frac{n_{	ext{Chlorobenzene}}}{n_{	ext{water}}} = \frac{P_{	ext{Chlorobenzene}}^{o}}{P_{	ext{Water}}^{o}}$Or, $\frac{x/112.5}{(100 - x)/18} = \frac{9.031 	imes 10^{4} - 7.031 	imes 10^{4}}{7.031 	imes 10^{4}} \Rightarrow x = 64$

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