SolutionHard
Question
A liquid solution is formed by mixing 10 moles of aniline and 20 moles of phenol at a temperature where the vapour pressures of pure liquid aniline and phenol are 90 and 87 mm Hg, respectively. The possible vapour pressure of solution at that temperature is
Options
A.82 mm Hg
B.88 mm Hg
C.90 mm Hg
D.94 mm Hg
Solution
If the solution were ideal,
$P_{\text{total}} = \frac{10}{30} \times 90 + \frac{20}{30} \times 87 = 88\text{ mm kg}$
As the solution of phenol and aniline shows negative deviation, the V.P. must be less than 88 mm kg.
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