SolutionHard
Question
Pure benzene freezes at 5.45o CA 0.374 m solution of terachloroethane in benzene freezes at 3.35o C. The Kf for benzene is :
Options
A.0.508
B.5.08
C.50.8
D.508
Solution
ᐃTf = Kf × m
(5.45 - 3.55) = Kf × 0.374
Kf =
= 5.08
(5.45 - 3.55) = Kf × 0.374
Kf =
= 5.08Create a free account to view solution
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