SolutionHard
Question
If 0.1 molal aqueous solution of sodium bromide freezes at −0.3348°C at one atmospheric pressure, then the percent dissociation of salt in the solution is (Kf = 1.86)
Options
A.90
B.80
C.60
D.20
Solution
$\Delta T_{f} = K_{f}.m \Rightarrow 0.3348 = 1.86 \times 0.1(1 + \alpha) \Rightarrow \alpha = 0.8$
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