Aqueous solutions of 0.004 M-Na2SO4 and 0.01 M-Glucose are isotonic. The percentage dissociation of

Question

Aqueous solutions of 0.004 M-Na2SO4 and 0.01 M-Glucose are isotonic. The percentage dissociation of Na2SO4 is

Accepted Answer

$\underset{0.004(1 - \alpha)M}{Na_{2}SO_{4}} \rightleftharpoons \underset{0.004 \times 2\alpha}{2Na^{+}} + \underset{0.004 \times \alpha}{SO_{4}^{2 -}}$

Effective molarity = 0.004(1 – α) + 0.008α + 0.004α = 0.004 + 0.008α

For solution to be isotonic,

0.004 + 0.008α = 0.01 ⇒ α = 0.75

Question

Options

Solution

More Solution Questions