SolutionHard

Question

The rise in the boiling point of a solution containing 1.8 g of glucose in 100 g of a solvent is 0.1°C. The molal elevation constant of the solvent is

Options

A.1 K/m
B.10 K/m
C.0.01 K/m
D.2731 K/m

Solution

$\Delta T_{b} = K_{b}.m \Rightarrow 0.1 = K_{b} \times \frac{1.8/180}{100/1000} \Rightarrow K_{b} = 1.0\text{ K/m}$

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