SolutionHard
Question
The rise in the boiling point of a solution containing 1.8 g of glucose in 100 g of a solvent is 0.1°C. The molal elevation constant of the solvent is
Options
A.1 K/m
B.10 K/m
C.0.01 K/m
D.2731 K/m
Solution
$\Delta T_{b} = K_{b}.m \Rightarrow 0.1 = K_{b} \times \frac{1.8/180}{100/1000} \Rightarrow K_{b} = 1.0\text{ K/m}$
Create a free account to view solution
View Solution FreeMore Solution Questions
Match the terms with definitionsTermI : Hemolysis]II : CrenationIII : HygroscopicIV : HypertonicV : IsotonicDefinition [...Which of the following compound does not give test of sulphate ion in aqueous solution :-...Which of the following is not a characteristic property of the polar liquids?...When 25 ml of CCl4 and 25 ml of toluene is mixed, the total volume of the solution will be...If 0.1 molar solution of glucose is separated from 0.1 molar solution of cane sugar by a semipermeable membrane, then wh...