A metallic element exists as cubic lattice. Each edge of the unit cell is 4.0 Å. The density of the

Question

A metallic element exists as cubic lattice. Each edge of the unit cell is 4.0 Å. The density of the metal is 6.25 g/cm3. How many unit cells will be present in 100 g of the metal?

Accepted Answer

Volume of metal taken = $\frac{m}{d} = \frac{100}{6.25} = 16\text{c}\text{m}^{3}$.

Volume of each unit cell = $\left( 4 \times 10^{- 8}\text{cm} \right)^{3} = 64 \times 10^{- 24}\text{c}\text{m}^{3}$

∴ Number of unit cells = $\frac{16}{64 \times 10^{- 24}} = 2.5 \times 10^{23}$

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