Solid StateHard

Question

The densities of ice and water at 0°C and 1 bar are 0.96 and 0.99 g/cm3, respectively. If the percentage of occupied space in ice is x, then the percentage of empty space in water is

Options

A.$\frac{32}{33}x$
B.$\frac{33}{32}x$
C.100 −$\frac{33}{32}x$
D.100−$\frac{32}{33}x$

Solution

Percentage of occupied space in water = $x \times \frac{0.99}{0.96} = \frac{33x}{32}$

∴ Percentage of empty space in water is $100 - \frac{33x}{32}$. X=percentage of occupied space

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