Solid StateHard
Question
What is the void space per unit cell for metallic silver crystallizing in the FCC system, the edge length of the unit cell being 4 Å?
Options
A.47.36 Å3
B.30.72 Å3
C.20.48 Å3
D.16.64 Å3
Solution
Void space per unit cell = 0.26 × Vunitcell
$= 0.26 \times V_{\text{unit cell}} = 0.26 \times \left( 4\overset{o}{A} \right)^{3} = 16.64{\overset{o}{A}}^{3}$
Create a free account to view solution
View Solution FreeMore Solid State Questions
Lithium crystallizes in a body centered cubic lattice. How many next–nearest neighbors does each Li have?...In the zinc blend structure (ZnS), S2− adopts CCP arrangement and Zn2+ occupies...A solid contains An+ and Bm− ions. The structure of solid is FCC for Bm− ions and An+ ions are present in one-fourth of ...The coordination number of cation and anion in Fluorite CaF2 and Rutile TiO2 are respectively :...The composition of a sample of cuprous oxide is found to be Cu1.92O1.00 due to metal deficient defect. The molar ratio o...