Ionic EquilibriumHard
Question
Calculate Kform for HgCl42− if the concentration of Hg2+ is 1.6 × 10–17 M in a solution prepared by dissolving 0.10 mole of Hg(NO3)2 in 1 L of solution containing 0.9 mole of NaCl.
Options
A.1017 b) 1016
B.1018
C.6.25 × 1016
Solution
$Hg^{2 +} + 4Cl^{-} \rightleftharpoons HgCl_{4}^{2 -}$
0.1 M 0.9 M 0
100% ram 0 0.5 M
Eqn. $1.6 \times 10^{- 17}\text{ M}$ 0.1 M
$\therefore K_{\text{form}} = \frac{0.1}{1.6 \times 10^{- 17} \times (0.5)^{4}} = 10^{17}$
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