Ionic EquilibriumHard
Question
A volume of 18 ml of acetic acid mixture and sodium acetate required 6 ml of 0.1 M-NaOH for neutralization of the acid and 12 ml of 0.1 M-HCl reaction with salt separately. If pKa of acetic acid is 4.75, then what is the pH of the mixture? (log 2 = 0.3)
Options
A.5.05
B.4.45
C.4.15
D.5.35
Solution
Millimoles of ACOH = 6 × 0.1 = 0.6
Millimoles of ACO– = 12.× 0.1 = 1.2
$\therefore P^{H} = 4.75 + \log\frac{1.2}{0.6} = 5.05$
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