A volume of 18 ml of acetic acid mixture and sodium acetate required 6 ml of 0.1 M-NaOH for neutrali

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A volume of 18 ml of acetic acid mixture and sodium acetate required 6 ml of 0.1 M-NaOH for neutralization of the acid and 12 ml of 0.1 M-HCl reaction with salt separately. If pKa of acetic acid is 4.75, then what is the pH of the mixture? (log 2 = 0.3)

Accepted Answer

Millimoles of ACOH = 6 × 0.1 = 0.6Millimoles of ACO– = 12.× 0.1 = 1.2$	herefore P^{H} = 4.75 + \log\frac{1.2}{0.6} = 5.05$

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