How many moles of acetic acid should be added to 100 ml of 0.6 M formic acid solution such that the

Question

How many moles of acetic acid should be added to 100 ml of 0.6 M formic acid solution such that the percentage dissociation of formic acid remains unchanged? The value of Ka for acetic acid = 1.8 × 10−5 and Ka for formic acid = 2.4 × 10−4.

Accepted Answer

$\left\lbrack H^{+} ightbrack_{HCOOH} = \left\lbrack H^{+} ightbrack_{CH_{3}COOH}$Or, $\sqrt{2.4 	imes 10^{- 4} 	imes 0.6} = \sqrt{1.8 	imes 10^{- 5} 	imes C} \Rightarrow C = 8	ext{ M}$∴ Moles of CH3COOH added = $\frac{100 	imes 8}{1000} = 0.8$

Question

Options

Solution

More Ionic Equilibrium Questions