Ionic EquilibriumMedium
Question
The following five solutions of KOH were prepared as first, 0.1 mole in 1 L; second, 0.2 mole in 2 L; third, 0.3 mole in 3 L; fourth, 0.4 mole in 4 L; fifth, 0.5 mole in 5 L. The pH of resultant solution, when all these solutions are mixed is
Options
A.2
B.1
C.13
D.7
Solution
As all have 0.1 M concentration, [KOH]final = 0.1 M
∴ POH = – log(0.1) = 1.0 and PH = 13
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