Ionic EquilibriumMedium
Question
What is the pH of 10−7 M-HCl solution at 25o C?
Options
A.7.0
B.6.70
C.6.62
D.6.79
Solution
As the acid is very dilute, the contribution of water should be taken. Let H2O dissociates only upto xM in presence of HCl.
H2O $\rightleftharpoons$ H+ + OH–
Equilibrium (x + 10–7) M x M
Now, [H+][OH–] = Kw ⇒ (x + 10–7) ⋅ x = 10–14
⇒ x = 6.18 × 10–8
∴ [H+] = (x + 10–7) M = 1.618 × 10–7 M
⇒ PH = 6.79
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