Ionic EquilibriumMedium
Question
The pH of 0.005 M-NaOH solution is (log 2 = 0.3)
Options
A.2.3
B.2.7
C.11.3
D.11.7
Solution
POH = –log(0.005) = 2.3
∴ PH = 14 – 2.3 = 11.7
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