Ionic EquilibriumHard
Question
The pH of 0.005 M-NaOH solution is (log 2 = 0.3)
Options
A.2.3
B.2.7
C.11.3
D.11.7
Solution
POH = –log(0.005) = 2.3
∴ PH = 14 – 2.3 = 11.7
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
Which of the following are true for an acid-base titration ?...When weak base solution (50 ml of 0.1 N NH4OH) is titrated with strong acid 0.1 N HCl, the pH of solution initially decr...0.1mol HCl is dissolved in distilled water of volume V then at limV→∞ (pH)solution is equal to...To a solution of acetic acid, solid sodium acetate is gradually added. When ‘x g’ of the salt has been added, the pH has...To 0.35 L of 0.1 M – NH3 0.15 L of 0.1 M-MgCl2 is added. What minimum mass of (NH4)2SO4 should be added to cause the Mg(...